such that f(ab)=f(a)f(b)
Evidently, linear mapping
E(x)=x
is linear automorphism.
In quaternion algebra there are nontrivial linear automorphisms. For instance
Similarly, the mapping
In the paper eprint arXiv:1107.1139, Linear Mappings of Quaternion Algebra, I proved following statement. For any linear over real field function $f$ there is unique expansion f(x)=a0E(x)+a1E1(x)+a2E2(x)+a3I(x)
No comments:
Post a Comment